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A bag contain 5 blue and 4 black balls. Three balls are drawn at random. What is the probability that 2 are blue and 1 is black.

n(S)=9C3 n(E)=(5C2*4C1)

p(E)=n(E)/n(S) =(5C2*4C1)/9C3........simplify

P(E)=10/21

Ans is 10/21 probability

probability=10/21

p(E)= 5c2 *4c1 / 9c3 = 10/21

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