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A bag contain 5 blue & 4 black balls. 3 balls are drawn at random, what is the probability of 2 are blue and 1 is black?

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A bag contain 5 blue and 4 black balls. Three balls are drawn at random. What is the probability that 2 are blue and 1 is black.

posted Nov 13, 2015 by anonymous

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2 Answers

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n(S)=9C3
n(E)=(5C2*4C1)

p(E)=n(E)/n(S)
=(5C2*4C1)/9C3........simplify

P(E)=10/21

Ans is 10/21 probability

answer Nov 13, 2015 by Jaikumar Bhatia
0 votes

probability=10/21

 p(E)= 5c2 *4c1 / 9c3 = 10/21
answer Mar 14, 2016 by Ajay Kumar Topno



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