A- 36, B- 4, C- 9, D- 35, E- 24 one of solutions

BCD=1260 --- (1)

B+C+D = 2E --- (2) and E has to be even. Hence, sum of B, C and D must be even number such that (B+C+D)/2 is also even.

A = 0.5(B+C+D+E) which implies 2A = 3E --- (3)

By prime factorization, 1260 = 22 ´ 32 ´ 5 ´ 7

By permutation of B, C and D such that product of BCD will give 1260, there are a couple of acceptable answers.

Note that there are other possible solutions as B, C, D are interchangeable answers.