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If the sum of the digits of a three digit number is 17, and the sum of the squares of its digits is 109...

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The sum of the digits of a three digit number is 17, and the sum of the squares of its digits is 109. If we subtract 495 from the number, we shall get a number consisting of the same digits written in the reverse order. Find the number.

posted Mar 21, 2016 by Vijay

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1 Answer

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Ans:The three digit number is 863.
(8+6+3)=17
(8^2+6^2+3^2)=(64+36+9)=109
863-495=368..........(368 is reverse of 863).

answer Mar 21, 2016 by Jaikumar Bhatia



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