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- Thread starter Ene Dene
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lightgrav

Homework Helper

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is the *distance* from the center-of-charge, so

you might as well NOT displace the charge from the origin.

Second, the potential inside a NON-CONDUCTING sphere

that has been given UNIFORM CHARGE DENSITY

is V = kQr/R^2 .

I'm guessing that your book is pretending to not know

that we live in 3-d. With a 3-d situation l = 1 .

If your drawing doesn't have an "l" in it, then

you can't have an "l" in a formula derived about it!

If you want to call "l" the distance from the origin,

then this makes the drawing NOT symmetric,

so you'll never end up with a symmetric formula.

- #3

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I was talking about potential in spherical coordinates (I should have said so). If you have a charge on z asix displaced by unit value it will be proportional to:

1/|

Where P is Lagrande polynom.

If you put a sphere around an origin, and charge on north pole of that sphere, than the potential is proportional 1/r^(l+1) outside that sphere, and to r^l inside sphere, where l is a order of multipole. (for exampe, dipole l=2).

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