A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?

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A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?

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6 litres from each can!

Say the ratio of 12 litre from first container = X, and ratio of 12 litre from second container = Y,

then comparing ratios of milk from each container to final ratio of milk in 12 litre,

=> 3/4X+1/2Y = 5/8

similarly, comparing ratios of water from each container to final ratio of water in 12 litre,

1/4X+1/2Y = 3/8

Solving both equations we get, X=1/2 and Y=1/2...so we will get 12/2 = 6 litres from each container.

check: 3/4*1/2+1/2*1/2 = 3/8+1/4 = 5/8

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