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What is the value of X if X=a+b+c+d+3 and x/5=a, x/8=b, x/6=c, x/2=d

x = 360 x = 1/5*x + 1/8*x + 1/6*x + 1/2*x + 3 x = 24/120*x + 15/120*x + 20/120*x + 60/120*x + 3 x = 119/120*x + 3 1/120*x = 3 x = 360

Ans is: X=360 .............so simple

x = (12x+7.5x+10x+30x+180)/60 60x = 59.5x+180 0.5x=180 x=360

480X = 96X+60X+80X+240X+(3x480) 480X - 476X = 1440 X = 1440/4 = 360

x=360 i.e x = a+b+c+d = x/5 + x/8 + x/6 + x/2 +3..............(1)

multiplying eqn 1 above by 120 (LCM of 5,8,6,2) throught,

120x = 24x + 15x + 20x + 60x+ 360 = 119x +360 120x - 119x =360

x = 360

x/5+x/8+x/6+x/2+3=x (96x+60x+80x+240x+1440)/480=x (476x+1440)/480=x 476x/480+3=x x-476x/480=3 4x/480=3 4x=1440 x=360

substituting the values of a,b,c,and d we get x=360 hence x=360

Ans: The Value of X is : 360

x = 360 x = 1/5*x + 1/8*x + 1/6*x + 1/2*x + 3 x = 24/120*x + 15/120*x + 20/120*x + 60/120*x + 3 x = 119/120*x + 3 1/120*x = 3 so the right answer is x=360...

If

a+b=8, a+c=13, b+d=8, c-d=6

Then

a, b, c, d = ??