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From a point A on a level ground, the angle of elevation of the top tower is 30º. If the tower is 100 m high, the distance of point A from the foot of the tower is:

Answer is 173 m sin30 = 100 / hyp side

hyp side = 200 Now for distance of point A from the foot of the tower =cos30 * hyp side = 0.866 * 200 = 173 m

Distance from A to bottom of tower=P Height of tower =100m Angle of elevation from point A=30° Therefore Tan 30°=100/P P=100/tan30° =100/(1/√3) =173 So ans is 173m

Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation of the top of the lighthouse is observed from the ships are 60° and 30° respectively. If the lighthouse is 144 m high, what is the distance between the two ships?

From a point P on a level ground, the angle of elevation of the top tower is 30º. If the tower is 100 m high, Then what is the the distance of point P from the foot of the tower.

At a particular time the shadow of a men of 170 cm height is 204 cm on the ground and at the same time and on the same ground the shadow of a pole is 600 cm. Find the height of the pole?

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