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From a point A on a level ground, the angle of elevation of the top tower is 30º. If the tower is 100 m high, the distance of point A from the foot of the tower is:
Answer is 173 m
sin30 = 100 / hyp side
hyp side = 200
Now for distance of point A from the foot of the tower =cos30 * hyp side = 0.866 * 200 = 173 m
Distance from A to bottom of tower=P
Height of tower =100m
Angle of elevation from point A=30°
Therefore Tan 30°=100/P
So ans is 173m
Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation of the top of the lighthouse is observed from the ships are 60° and 30° respectively. If the lighthouse is 144 m high, what is the distance between the two ships?
From a point P on a level ground, the angle of elevation of the top tower is 30º. If the tower is 100 m high, Then what is the the distance of point P from the foot of the tower.
At a particular time the shadow of a men of 170 cm height is 204 cm on the ground and at the same time and on the same ground the shadow of a pole is 600 cm. Find the height of the pole?
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It is given that the sun rays make an angle of 45 degree with the horizon
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