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What will be the output of below c program?

+3 votes
129 views

1.

main()
{
printf("%x",-1<<4);
}

2.

main()
{
int i=10;
i=!i>14;
Printf ("i=%d",i);
}
posted Mar 28, 2015 by Amit Kumar Pandey

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Why don't you try it on any onine C compiler?

1 Answer

+3 votes
  1. Depending on the machine implementation it will result in FFFFFF0 (for 32bit ) or FFF0 (16 bit )

  2. I = 0 . In the expression !i>14 , NOT (!) operator has more precedence than ? >? symbol. ! is a unary logical operator. !i (!10) is 0 (not of true is false). 0>14 is false (zero).

answer Mar 28, 2015 by Tanmoy Debnath
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Please provide your explanation also?

0 votes
#include<stdio.h>
main()
{
        int a=10;
        printf("%d\n",a++==a);
}

Output should be 1 but it is coming as 0,
Can anyone please explain?

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