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How to covert unsigned char[4] to unsigned integer?

+3 votes
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How to covert unsigned char[4] to unsigned integer?
posted Feb 17, 2015 by anonymous

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1 Answer

0 votes

I would like to explain by using following sample piece of code:
char[4] ch = {'1', '2', '3', '4'};
int i = 0;
n = 4;
for (i = 0; i < n ; i++)
{
i += (ch[i] - '0') * pow(10, n-i-1);
}

Now, i has converted integer value of i

answer Feb 17, 2015 by Harshita
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A char can not be a +ve or -ve. last bit is signed bit in accumulator.but not useful for CHAR Whats the purpose? of doing it.

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