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Write a program in C for changing case of given input?

+2 votes
152 views
Input: My SpAce
Output: mY sPaCE
posted Nov 20, 2014 by anonymous

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main()
{
    int i;
    char name[9]="My SpAcE";
    char nam[9];
    printf("INPUT :%s",name);
    for(i=0;i<9;i++)
    {
        nam[i]= islower(name[i])?toupper(name[i]):tolower(name[i]);
       
    }
         printf("\nOUTPUT:%s\n",nam);

   
}

2 Answers

+2 votes
int main()
{
    char buff[100];
    int i = 0;
    printf("enter the input string\n");
    scanf("%[^\n]",buff);
    while(buff[i]){
       if(!(buff[i] ^= 32))
            buff[i] ^= 32;
       i++;
    }
    printf("case converted str :%s\n",buff);

}
answer Nov 20, 2014 by Bheemappa G
+2 votes

Here is my code(Tested).

Note:
You have to substract 32 if you want to change the char form lover to upper case and have to add 32 to that character for upper to lower case.
As ASCII value of A = 65 and Z = 90 and a = 97 and z = 127, and their difference is 32 i.e (a - A) or (z - Z).

#include <stdio.h>

int main()
{
    char str[10] = "My SpAce";
    int i;

    printf("String before change : %s\n", str);

    for (i = 0; str[i]; i++) {
        if (str[i] != ' ') {
           if (str[i] >= 'a' && str[i] <= 'z') {
                str[i] -= 32;
            } else if (str[i] >= 'A' && str[i] <= 'Z') {
                str[i] += 32;
            }
        }
   }

   printf("String After  change : %s\n", str);

   return 0;
}
answer Nov 20, 2014 by Arshad Khan
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