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Printing all permutations of a given string in C

+3 votes
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Please help me to print all permutations of a string in C?

posted Apr 10, 2014 by anonymous

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1 Answer

+2 votes

Source: http://www.geeksforgeeks.org/write-a-c-program-to-print-all-permutations-of-a-given-string/

Below are the permutations of string ABC.
ABC, ACB, BAC, BCA, CAB, CBA

Here is a solution using backtracking.
backtracking

# include <stdio.h>

/* Function to swap values at two pointers */
void swap (char *x, char *y)
{
    char temp;
    temp = *x;
    *x = *y;
    *y = temp;
}

/* Function to print permutations of string
   This function takes three parameters:
   1. String
   2. Starting index of the string
   3. Ending index of the string. */

void permute(char *a, int i, int n) 
{
   int j; 
   if (i == n)
     printf("%s\n", a);
   else
   {
        for (j = i; j <= n; j++)
       {
          swap((a+i), (a+j));
          permute(a, i+1, n);
          swap((a+i), (a+j)); //backtrack
       }
   }
} 

/* Driver program to test above functions */
int main()
{
   char a[] = "ABC";  
   permute(a, 0, 2);
   getchar();
   return 0;
}
answer Apr 11, 2014 by Atul Mishra
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