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C: Compress String with character and its count. Example: "aaabbba" -> "a3b3a1”

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C: Compress String with character and its count. Example: "aaabbba" -> "a3b3a1”
posted Aug 1, 2017 by anonymous

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Try this solution and compress for string

    #include <stdio.h>
    
    int main(void) {
        // your code goes here
        char string[100], output[25];
        // initializing each index with zero
        for(int i=0;i<26;i++) {
            output[i] = 0;
        }
        scanf("%[^\n]s", string);
        // getting count of each char
        for(int i=0;string[i] !='\0'; i++) {
       
        output[(int)string[i]-97]++;
        }
        int counter =0;

        for(int i=0;i<26;i++) {
            if(output[i]!=0) {
           
                printf("%c%d", (char)(i+97), output[i]);
                counter = 0;
            }
        }
        return 0;
    }
use this function to get size of new string so you dont waste memory

int size_of_cmp_string(char s[])
{
int i=0;
int new_size_of_string=0;

while(i != strlen(s))
{
if(i < strlen(s))
{

if(s[i] != s[i+1])
{new_size_of_string++;
i++;}
else
{
new_size_of_string++;
while(s[i] == s[i+1])
{
if((i+1) == strlen(s))
{break;}
i++;}}

}
}
return new_size_of_string;}

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Output
Enter the string: Welcome to C Class!
Enter the word to insert: programming
Enter the position you like to insert: 3
The string after modification is

Welcome to C programming Class!

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