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How to print a semicolon(;) without using semicolon in C/C++?

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How to print a semicolon(;) without using semicolon in C/C++?
posted Jul 26, 2017 by Ajay Kumar

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1 Answer

+3 votes
 
Best answer

Use following statement in C program:
printf("%c", 59);

ASCII value of semicolon is 59.

answer Jul 26, 2017 by Harshita
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1.No input should be processed, and the output should be in the form of 2 3 5 7 11 13 ... etc.
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