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Python: Transpose a matrix in Single line in Python?

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Python: Transpose a matrix in Single line in Python?
posted Jul 16, 2017 by Ajay Kumar

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I seem to stumble upon a situation where "!=" operator misbehaves in python2.x. Not sure if it's my misunderstanding or a bug in python implementation. Here's a demo code to reproduce the behavior -

From __future__ import unicode_literals, print_function

class DemoClass(object):
   def __init__(self, val):
   self.val = val

   def __eq__(self, other):
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  x = DemoClass('a')
  y = DemoClass('a')

  print("x == y: {0}".format(x == y))
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In python3, the output is as expected:

x == y: True
x != y: False
not x == y: False

In python2.7.3, the output is:

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+4 votes

Given a binary matrix, find out the maximum size square sub-matrix with all 1 s, Recusively

For example, consider the below binary matrix.
(Source:- geeksforgeeks

   0  1  1  0  1 
   1  1  0  1  0 
   0  1  1  1  0
   1  1  1  1  0
   1  1  1  1  1
   0  0  0  0  0

The maximum square sub-matrix with all set bits is

1  1  1
1  1  1
1  1  1

As we know it's general solution is with DP, but here i am interested in Recursive Approach

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I need a command that will make threads created by "multiprocessing.Process()" wait for each other to complete. For instance, I want to do something like this:

job1 = multiprocessing.Process(CMD1())
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The command "PY_FUNC()" depends on the end result of the actions of CMD1() and CMD2(). I need some kind of wait command for the two threads that will not let the script continue until job1 and job2 are complete. Is this possible in Python3?

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