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Any reason why printf() does not support formats with thousands separator in PHP?

0 votes

I've recently discovered that a format such as %'.2f" results in this:

php -r "printf("%'.2f", 23232323.237);"

I know that number_format() will do the same, but I am given the format spec as an interface, I would need to try to parse it and then decide whether to use printf() or number_format().

posted Jul 10, 2017 by anonymous

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Why ${0} is valid but ${0 is not valid? it means that curly braces evaluate what's inside them and that's why we
cannot have ${0?

Variables shouldn't start from 0 so it means that it started from braces? if yes why I cannot have ${0? and what is the variable here finally? $0 is what it interprets? if yes so it is not a legal variable.

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