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Why the following C code gives output: -2 -1 instead of 2 1?

+2 votes
struct marks {
  int a:1;
  int b:2;

int main() {
  struct marks obj={1,6};
  printf("%d %d\n",obj.b,obj.a);
posted Apr 28, 2017 by anonymous

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1 Answer

0 votes

This question is not as simple as it looks. What I interpreted that first field a and second field b both are signed integer type. If I consider a short int as 1 byte then its left most bit would signify (+/-) based on either left most bit is 0 or 1.
In this case though only one bit is reserved for member "a "but this bit would be considered for signed/unsigned also that's why when value 1 is assign to "a" and when it is printed it shows as -1.
Same concept of member "b" also.

answer Apr 29, 2017 by Harshita
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+3 votes

See the following code

void main(){
   float a=5.2;
  else if(a<5.2)
     printf("Less than");
     printf("Greater than"); 

Expected output is equal but we does not get same why?

0 votes

Write a C code for the logic -
input: string, strong
output: strng