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How to create multi processing in python?

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How to create multi processing in python?
posted Jun 18, 2016 by Ramachandran A

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2 Answers

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Best answer

The another way of creating multiprocessing using Pool

from multiprocessing import Pool
import time
import sys
import os
def fun(x):
print x
print 'Starting:', os.getpid()
print 'Exiting :'

if __name__ == '__main__':
p = Pool(processes=5)
d =,[1,2,3,4,4])

answer Jun 19, 2016 by Mohan Raj N
0 votes

The simplest way to spawn a second is to instantiate a Process object with a target function and call start() to let it begin working.

import multiprocessing

def worker():
    """worker function"""
    print 'Worker'

if __name__ == '__main__':
    jobs = []
    for i in range(5):
        p = multiprocessing.Process(target=worker)

I would suggest that you go through the following link which describes the multi processing using Python in great detail -

answer Jun 18, 2016 by Salil Agrawal
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I have a list of tuples where the number of rows in the list and the number of columns in tuples of the list will not be constant. i.e.

list = [(a1,b1, …z1), (a2,b2, …, z2),…. ,(am,bm, … , zm )]. It can be compared to the SQL results, as the number of columns change in the sql, the number of columns change in the list of tuples as well.

I have to iterate through each element of each tuple in the list, perform some checks on the value, convert it and return the modified values as a new list of tuples.

i.e.  list_value = [(‘name1’, 1234, ‘address1’ ), (‘name2’, 5678, ‘address2’), (‘name3’, 1011, ‘addre”ss3’)] 

I need to access each value to check if the value contains a double quote and enclose the string containing double quote with double quotes. The transformation should return

list_value = [(‘name1’, 1234, ‘address1’ ), (‘name2’, 5678, ‘address2’), (‘name3’, 1011, ‘”addre”ss3”’)] 

The simplest approach for me would be to do this:

mod_val = [transform(row) for row in list_value] 
def transform(row): 
   while index < len(row): 
...    if isinstance(row[index],basestring): 
...       if " in row[index]: 
...          mod_list.append("+row[index]+") 
...    else: 
...       mod_list.append(row[index]) 
...    index = index+1 
... return mod_list 

Is there a way to make the code concise using list comprehension?

0 votes

I'm in the first chapter of Natural Language Processing with Python and am trying to run the example .dispersion_plot. I am using Python 2.7.4 (Anaconda) on Mac OSX 10.8.

When I load all of the necessary modules and try to create the dispersion plott, I get no return - no plot, no error message, not even a new >>> prompt, just a blinking cursor under the last line I typed. Here is what I've been doing:

[~]: python
Python 2.7.4 |Anaconda 1.5.1 (x86_64)| (default, May 9 2013, 12:12:00) 
[GCC 4.0.1 (Apple Inc. build 5493)] on darwin
Type "help", "copyright", "credits" or "license" for more information.

>>> import numpy
>>> import matplotlib
>>> import nltk
>>> from import *
*** Introductory Examples for the NLTK Book ***
Loading text1, ..., text9 and sent1, ..., sent9
Type the name of the text or sentence to view it.
Type: 'texts()' or 'sents()' to list the materials.
text1: Moby Dick by Herman Melville 1851
text2: Sense and Sensibility by Jane Austen 1811
text3: The Book of Genesis
text4: Inaugural Address Corpus
text5: Chat Corpus
text6: Monty Python and the Holy Grail
text7: Wall Street Journal
text8: Personals Corpus
text9: The Man Who Was Thursday by G . K . Chesterton 1908
>>> text4.dispersion_plot(["citizens", "democracy", "freedom", "duties", "America"])

...and nothing. I can't paste it but my cursor is just blinking under my last command with no prompt. So far the other example commands from the chapter (e.g. .concordance) work fine, so I'm guessing the problem is something with numpy or matplotlib. I had a heck of a time getting matplotlib installed correctly (kept getting errors saying that it wasn't installed even when I had installed it), but since switching to the Anaconda distro, which had those prepackaged, I haven't gotten any module errors.

Any advice??

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