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Which declaration gives error in JAVA and why?

+1 vote
1)double d=0786; 

2)double d=0x4b17;
posted Feb 13, 2016 by anonymous

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1 Answer

+2 votes

double d=0786; will give the compilation error in Java (integer number too large: 0786). Numbers beginning with 0 are considered octal and allowed digits are 0-7 and 8 is not allowed.

Any number starting with 0x is hex number and allowed digits are 0-9,a-f hence there is no issue with second statement.

answer Feb 13, 2016 by Salil Agrawal
Similar Questions
+1 vote

Why the following program gives an error?

#include <stdio.h>

int main() 
    unsigned int64_t i = 12;
    printf("%lld\n", i);
    return 0;


 In function 'main':
5:19: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'i'
  unsigned int64_t i = 12;
5:19: error: 'i' undeclared (first use in this function)
5:19: note: each undeclared identifier is reported only once for each function it appears in

But, If I remove the unsigned keyword, it's working fine. So, Why unsigned int64_t i gives an error?

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