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What gets printed when the following program is compiled and run?

+1 vote
91 views
class test
 {
    static boolean check;
    public static void main(String args[])
   {
        int i;
        if(check == true)
            i=1;
        else
            i=2;
        if(i=2) i=i+2;
        else i = i + 4;
        System.out.println(i);
     }
}
posted Jan 12, 2016 by Divya Shree

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2 Answers

+1 vote

Although the program won't run because of if(i=2) but if your condition become
if(i==2) instead of if(i=2) then output=4

answer Feb 12, 2016 by Shivam Kumar Pandey
0 votes

The program does not compile because of the statement if(i=2).

The statement "i=2" evaluates to 2. The expression within the if block must evaluate to a Boolean.

answer Jan 12, 2016 by Kavana Gowda
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+2 votes
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    public static void main(String args[]) { 
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