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DS: Write program to reverse a singly linked list ?

+3 votes
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DS: Write program to reverse a singly linked list ?
posted Dec 10, 2015 by Vikram Singh

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2 Answers

+1 vote

Any one can also see this java code implementation

public class LinkedListExample {
    private Node head;

    public LinkedListExample(Node node) {
        this.head = node;
    }

    public static void main(String[] args) {
        Node node = new Node(1);
        LinkedListExample list = new LinkedListExample(node);
        list.add(new Node(8));
        list.add(new Node(4));
        list.add(new Node(9));

        list.display();

        list.reverse();

        list.display();
    }

    public void add(Node node) {
        Node current = head;
        while (current != null) {
            if (current.next() == null) {
                current.setNext(node);
                break;
            }
            current = current.next();
        }
    }

    public void display() {
        Node node = head;
        while (node != null) {
            System.out.print(node.data() + " ");
            node = node.next();
        }
        System.out.println("");
    }

    public void reverse() {
        Node pointer = head;
        Node previous = null, current = null;
        while (pointer != null) {
            current = pointer;
            pointer = pointer.next();
            // reverse the link
            current.setNext(previous);
            previous = current;
            head = current;
        }
    }

}

class Node {
    private int data;
    private Node next;

    public Node(int data) {
        this.data = data;
    }

    public int data() {
        return data;
    }

    public Node next() {
        return next;
    }

    public void setNext(Node next) {
        this.next = next;
    }
}

OUTPUT

1 8 4 9 
9 4 8 1 
answer Sep 28 by Atindra Kumar Nath
0 votes

This program reverses a singly linked list. We have defined seperate function for each operation. 7 fuctions have been define here : 'insertend' for insertion at end of linked list, 'insertmid' for insertion after a given node, 'insertbeg' for insertion at starting of linked list, 'reverse' to reverse the list, 'del' to delete a node, 'display' to display the linked list and 'count' to count the number of nodes in linked list.

Code:

#include<stdio.h>
#include<conio.h>
struct node
{
int info;
struct node *link;
};
struct node *start,*newptr;
struct node *create_new_node(int i);
void insertend(struct node *n);
void insertmid(struct node *o);
void insertbeg(struct node *m);
void reverse(int c);
void del(int d);
void display(struct node *x);
int count(struct node *c);
void main()
{
int info,a,c;
struct node *np;
char ch;
start=NULL;
clrscr();
do
{
printf("ENTER YOUR CHOICE:\n");
printf("Enter 1 to insert at begining\n");
printf("Enter 2 to insert after a given element\n");
printf("Enter 3 to insert at end\n");
printf("Enter 4 to delete a particular element\n");
printf("Enter 5 to reverse the current linked list\n");
scanf("%d",&a);
if(a==1)
{
printf("Enter the element\n");
scanf("%d",&info);
np=create_new_node(info);
insertbeg(np);
}
else if(a==2)
{
printf("Enter the element\n");
scanf("%d",&info);
np=create_new_node(info);
insertmid(np);
}
else if(a==3)
{
printf("Enter the element\n");
scanf("%d",&info);
np=create_new_node(info);
insertend(np);
}
else if(a==4)
{
printf("Enter the element\n");
scanf("%d",&info);
np=create_new_node(info);
del(info);
}
else if(a==5)
{
reverse(c);
}
display(start);
c=count(start);
printf("The number of nodes are %d\n",c);
printf("\nDo you want to proceed? y/n\n");
scanf(" %c",&ch);
}
while(ch=='y');
getch();
}
/*CREATION OF NEW NODE*/
struct node *create_new_node(int i)
{
newptr=(struct node *)malloc(sizeof(struct node));
newptr->info=i;
newptr->link=NULL;
return newptr;
}
/*INSERTION AT BEGINING*/
void insertbeg(struct node *m)
{
if(start==NULL)
{
start=m;
}
else
{
m->link=start;
start=m;
}
}
/*INSERTION AT END*/
void insertend(struct node *n)
{
struct node *temp;
if(start==NULL)
{
start=n;
}
else
{
temp=start;
while(temp->link!=NULL)
temp=temp->link;
temp->link=n;
}
}
/*INSERTION AFTER A GIVEN ELEMENT*/
void insertmid(struct node *o)
{
int value;
struct node *temp;
temp=start;
printf("Enter the number after which ");
printf("new element has to be inserted:\n");
scanf("%d",&value);
while(temp!=NULL)
{
if(temp->info==value)
{
o->link=temp->link;
temp->link=o;
}
temp=temp->link;
}
}
/*DELETE*/
void del(int d)
{
struct node *temp,*ptr;
temp=start;
while(temp!=NULL)
{
if(temp->link->info==d)
{
ptr=temp->link;
temp->link=ptr->link;
free(ptr);
}
temp=temp->link;
}}
/*REVERSE*/
void reverse(int c)
{
struct node *p1,*p2,*p3;
if(start->link==NULL)
return;
p1=start;
p2=p1->link;
p3=p2->link;
p1->link=NULL;
p2->link=p1;
while(p3!=NULL)
{
p1=p2;
p2=p3;
p3=p3->link;
p2->link=p1;
}
start=p2;
}
/*DISPLAY*/
void display(struct node *x)
{
printf("\nCurrent linked list is:\t");
do
{
printf("%d\t",x->info);
x=x->link;
}
while(x!=NULL);
printf("\n");
}
/*COUNT THE NO. OF NODES*/
int count(struct node *c)
{
int co=0;
do
{
co++;
c=c->link;
}
while(c!=NULL);
return co;
}

Output

enter image description here

answer Dec 11, 2015 by Shivaranjini
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