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On the driver's arrival the photographer could set the right time on his watch. Can you tell me how?

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A wildlife photographer along with his driver was moving through an African jungle in his jeep. The jungle was dense and the road bumpy. The jeep accidentally hit a rock and the two men were thrown from their seats. The photographer's digital watch fell from his breast pocket and its battery popped out. Neither of them knew the correct time to re-synchronize the watch.
Thus the photographer asked his driver to visit the nearest forest officer's home and inquire the time. The driver drove the jeep at a constant speed to the forest officer's place, asked him the time, rested there for 5 mins and drove back to the jungle at the same speed at which he had gone. On the driver's arrival the photographer could set the right time on his watch. Can you tell me how?

Note - The driver did not have his own watch and neither did the forest office have a spare one which he could lend to the driver to take back with him.

posted Sep 4, 2015 by Sandeep Bedi

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3 Answers

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Best answer

Assume that when the driver left, the photographer had tuned his watch to a random time of 2:00 PM.

Let the total travel time of the driver be 2t, as he drove with the same speed on his forward and backward journey.

On the driver's return, the photographer's watch read (12 + 5/60 + 2t). From this he could find out the value of t. The driver's journey from the time he quit the forest officer's home was T+t ( T being the time the driver noted while setting back for the jungle from the forest officer.) Since both the quantities are known the correct time could be determined.

answer Sep 5, 2015 by Salil Agrawal
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They put the battery of the digital watch back in place and gave it to the driver before he went to the forest officer's home.

answer Sep 5, 2015 by Jcm
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If the time in photographer's watch was say 4 pm at the time of stoppage & the driver told him that the forest officer's watch showed 4:30 pm, then the current time will be 5:05 pm (By adding 5 minutes to the time taken by the driver to reach the forest officer's house i.e. 30 minutes)

answer Sep 5, 2015 by anonymous



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