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How many litres of liquid A was contained by the can initially.

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A can contains a mixture of two liquids A and B in proportion 7:5. When 9 litre of mixture are drawn off and the can is filled with B, the proportion of A and B becomes 7:9.
How many litres of liquid A was contained by the can initially.

posted Aug 19, 2015 by Balwinder

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1 Answer

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Proportion of liquid A and B is 7:5
A/B =7/5 that is 7B=5A implies 7B-5A=0 .................eq (1)

9 litr mixture water drawn off , so remining of liquid A is 7*9/12 = 5.25 and that of liquid B is 5*9/12 =3.75

After filling liquid B, the proportion becomes 7:9
That is (7A-5.25)/(5B-3.75+9B) = 7A/9B ..................eq(2)

solving the above two equations, we get A= 21 liter

answer Aug 20, 2015 by Jyoti Mhaske



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