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41152263*3=123456789 and (2^3) / 7 = 1 (remainder) , hence we have the remainder as 1
Ans is 1.
2^129456789 can be written as (2^3)^43152263.
By expanding the above expression...we get the result as 7*k + 1^43152263.
So the remainder is 1.
find the middle term of the sequence formed by all three digits numbers which leave a reminder 3, when divided by 4. Also find the sum of all numbers on both sides of the middle term separately.
A positive integer N leaves the same remainder of 35 when divided by both 2009 and 2010.
What is the remainder when N is divided by 42?
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