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A speaks truth in 70% cases and B in 80% cases. What will be the probability that they will contradict each other in describing a single event?
Pa(T)= .7 ;; probability of truth
Pa(L)= .3 ;; probability of lie
for B ,,
for contradiction probability = Pa(T)*Pb(L) + Pa(L)*Pb(T)
= .7*.2 + .3*.8
3 red, 2 white and 3 green balls are available in a bag. 2 balls are drawn one by one from the bag.
What will be the probability of one ball is white & other is green?
There are two bags. First contain 10 white balls and other contain 8 red balls. One ball from any bag shifted to other bag at random.
What will be the probability the second ball taken after first event would be red ?
First event is to drawn first ball.
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