(a) 49 (b) 48 (c) 99 (d) 1

here f(a/99) + f(1 - a/99) =1 === f(1/99) + f(98/99) = 1 ====f(2/99) + f(97/99) = 1 ...................... .... so we get 49 as answer

The function f (x) = | x - 2 | + | 2.5 - x| + |3.6 -x|, where x is a real number, attains a minimum at ??

If x + 1/x = 5 then x^2 + 1/x^2 = ??

If (Sqrt3)^5 * (9^2) = (3^x)*(3*Sqrt3) Then x=??

x, y, z and k are four non zero positive integers satisfying 1/x + y/2 = z/3 + 4/k, minimum integral value of k for integral value of x, y and z will be