# How many minimum diamonds they steal?

+1 vote
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There are seven thieves, They steal diamonds from a diamond merchant and run away in jungle. While running, night sets in and they decide to rest in the jungle When everybody’s sleeping, two of the best friends get up and decide to distribute the diamonds among themselves and run away. So they start distributing but find that one diamond was extra. So they decide to wake up 3rd one and divide the diamonds again …..only to their surprise they still find one diamond extra. So they decide to wake up fourth one. Again one diamond is spare. 5th woken up……still one extra. 6th still one extra. Now they wake up 7th and diamonds are distributed equally.

How many minimum diamonds they steal?

posted May 1, 2014

+1 vote

The number of diamonds should be divisible by 7 , and should leave remainder 1, when divided by 2,3,4,5,6.
LCM of 2,3,4,5,6= 60
=> the number can be written as 60k+1 which is divisible by 7
=> By trial and error we get n=5, therefore the number is 301

Similar Puzzles

7 thieves rob a diamond merchant of some diamonds.

When everybody was sleeping, two of them woke up and decided to divide the diamonds equally among themselves.

But when they divided the diamonds equally, one diamond is left.

So they woke up the 3rd thief and tried to divide the diamonds equally again but still one diamond was left.

Then they woke up the 4th thief to divide the diamonds equally again, and again one diamond was left.

This happened with the 5th and 6th thief – one diamond was still left.
Finally, they woke up the 7th thief and this time the diamonds were divided equally.

How many diamonds did they steal in total?

+1 vote

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