Event = {(1,5),(2,4),(3,3),(4,2),(5,1)} Therefore, P(getting sum = 6) = 5/36

36(permutations) possible outcomes are there in total. For a sum of 6 we have 5 possibilities- (1,5), (5,1),(2,4),(4,2) and (3,3)

Ans: 5/36