# What will be the product of all the digit of the choosen number ?

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A five digit number is choosen in such a way that ten's place is one less than unit's place, hundred's place is one less than ten's place and similarly the other digits. Sum of all the digits of a number obtained by adding that choosen number and the number formed by reversing its digit is 40.

What will be the product of all the digit of the choosen number ?

posted Jan 30, 2015

23456 are the 5 digits, which is the chosen number
When reverse it becomes 65432
So
Sum of digits is 40
2+3+4+5+6+6+5+4+3+2=40
So product of chosen number digit is 2*3*4*5*6 = 720

answer Jan 30, 2015

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A six digit number has the maximum number of possibilities of perfect square as given below
1. First digit is a perfect square
2. Second digit is a perfect square
3. Third digit is a perfect square
4. Number formed by first and second digit in order is perfect square
5. Number formed by third and fourth digit in order is perfect square
6. Number formed by fifth and sixth digit in order is perfect square
7.Number formed by last three digit in order is perfect square
Here sixth digit means the units place.
All the digits in the number are different and non zero.

What will be the product of all the six digit ?