xy/100 + yz/100 = zx/100

y = xz/(x+z)

If either x or z is one then no possible case because n/(n+1) will never a perfect square.

For x=2 and z=2, y=1 (Perfect square)

Similarly for x=8 and z=8, y=4 (Perfect square)

For x=3 and z=9, sum=12

so y = 3*9/12 = 9/4 (Perfect square)

so (3,9) and (9,3) are possible pair

So total possible pairs are (2,2), (8,8), (3,9) and (9/3)

so answer is **4 ways**