A sack contains 4 different colored balls (blue, yellow, red, and pink) of which 14 balls are not blue, 16 balls are not yellow, 24 balls are not red, and 12 balls are not pink.
How many balls are in the sack?
Let the total number of balls is t.
b + y + r + p = t
Also we have:
14 = t - b
16 = t - y
24 = t - r
12 = t - p
Sum up the above 4 equations:
66 = 4t - (b+y+r+p)
66 = 3t
22 = t
The answer would be 22 but there is a contradiction where it say 24 balls are not red. It means the total should be greater than 24.
Considering the above there is no solution.
A bag contains 4 yellow, 5 red, 3 green and 4 black balls.
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If three balls are drawn one after the other with replacement, then what is the probability of getting balls of same colour?