A sack contains 4 different colored balls (blue, yellow, red, and pink) of which 14 balls are not blue, 16 balls are not yellow, 24 balls are not red, and 12 balls are not pink.
How many balls are in the sack?
Let the total number of balls is t.
b + y + r + p = t
Also we have:
14 = t - b
16 = t - y
24 = t - r
12 = t - p
Sum up the above 4 equations:
66 = 4t - (b+y+r+p)
66 = 3t
22 = t
The answer would be 22 but there is a contradiction where it say 24 balls are not red. It means the total should be greater than 24.
Considering the above there is no solution.
A box contains 4 red balls, 6 green and 8 black balls. Three balls are drawn at random find the probability that three balls are of different color?
A bag contains 5 white, 4 red and 3 black balls. A ball is drawn at random from the bag, what is the probability that it is not black?
A bag contains Red Balls and Black Balls. Two balls are drawn without replacement. The probability that both the balls drawn are red is 1/2. What is the minimum number of Red and Black Balls for which this probability is satisfied?
The four colours of Ludo are Red,Green, Blue and Yellow.
If Red = 27
Blue = 40
Green = 49
Yellow = ?