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If 6 + 2 = 40, 4 + 3 = 25, 6 + 6 = 72, 5 + 10 = 125 then 7 + 1 = ??

+1 vote
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If 6 + 2 = 40, 4 + 3 = 25, 6 + 6 = 72, 5 + 10 = 125 then 7 + 1 = ??
posted Nov 1, 2014 by anonymous

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6 Answers

+3 votes

7+1=7^2+1^2=49+1=50

Logic-- x^2+y^2=z
Such as 6+2=40
6^2+2^2=40

4+3=25
4^2+3^2=25

And so on .

answer Nov 1, 2014 by Amit Kumar Pal
+2 votes

Ans : 50

Solution:

number  = (square of 1st number + square of 2nd number)
6^2 + 2^2 = 36 + 4 = 40
4^2 + 3^2 = 16 + 9 = 25
6^2 + 6^2 = 36 + 36 = 72
5^2 + 10^2 = 25 + 100 = 125
---- so
7^2 + 1^2 = 49 + 1 = 50
answer Nov 3, 2014 by Arshad Khan
+1 vote

50.
6^2+2^2=40.
7^2+1^1=50.

answer Dec 4, 2014 by Abhikarsh Gupta
+1 vote

6*6 + 2*2 = 40
..........

7*7 + 1*1 = 50

answer Jan 12, 2015 by Shivaraj Kenche
0 votes

6*6+2*2=40
4*4+3*3=25
6*6+6*6=72
5*5+10*10=125
7*7+1*1=50

answer Nov 15, 2015 by Arthur Ludwiczak
0 votes

If 6 + 2 = 40, 4 + 3 = 25, 6 + 6 = 72, 5 + 10 = 125 then 7 + 1 = ??

6^2+2^2=36+4=40
4^2+3^2=16+9=25

6^2+6^2=36+36=72

5^2+10^2=25+100=125

7^2+1^2=49+1=50

50 is the answer

answer Nov 25, 2016 by Pragati Jaiswal
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