A tap can fill a cistern in 11 hours, but due to a leakage it took 13 hours to fill the cistern.

If the cistern is full, in what time will the cistern become empty due to leakage?

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A tap can fill a cistern in 11 hours, but due to a leakage it took 13 hours to fill the cistern.

If the cistern is full, in what time will the cistern become empty due to leakage?

0 votes

0 votes

Let V = volume of the full tank

If the tap is open, The tank is filled at a rate of V/11 l/hr

Now , because of a leak , an extra volume of water is added to the tank. Extra volume = 2 V/11

If the tap is closed, every 11 hours the tank loses 2V/11

then , after 2V/11 x 5 + 1V/11 , the tank is empty

therefore 11 x 5 + 5,5 = 60,5 hours

The answer is 60,5 hours

...

If the tap is closed, every 13 (not 11) hours the tank loses 2V/11.