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Given the series - 4; 7; 12; 21; 38; .........what is the seventh term?

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Given the series - 4; 7; 12; 21; 38; .........what is the seventh term?
posted Jun 10 by Mohammad

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1 Answer

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4 + (2+2^0) = 7
7 + (2 + 2^0 + 2^1) = 12
12 + (2 + 2^0 + 2^1 + 2^2) = 21
21 + (2 + 2^0 + 2^1 + 2^2 + 2^3) = 38
Therefore for nth term we gave
(2 + 2^0 + .... 2^(n-2)) + (2 + 2^0 + .... 2^(n-1))
For n=7 we have
(2 + 2^0 + .... 2^(5)) + (2 + 2^0 + .... 2^(6)) = 65 + 129 = 194.

answer Jun 12 by Tejas Naik
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