   # If FRAUD = 50, CROOK = 62, CHEAT = 37 then whats the code for CHINA = ?

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If FRAUD = 50, CROOK = 62, CHEAT = 37 then whats the code for CHINA = ? posted May 5

Given the question:
If FRAUD = 50, CROOK = 62, CHEAT = 37 then what is the code for CHINA = ?

The solution is:
Let's convert each letter into a number in the words like A is 1, B is 2, C is 3 and so on until Z is 26.
Then, add the numbers all together in the word.
For example, FRAUD = 6+18+1+21+4 = 50.
Following this, CHINA = 3+8+9+14+1 = 35. answer May 5

Replacing the letters by the alphabetic order:
FRAUD, 6+18+1+21+4 = 50
CROOK 3+18+15+15+11 =62
CHEAT 3+8+5+1+20= 37
Then,
CHINA 3+8+9+14+1=35 answer May 9 by anonymous

Add the position in the alphabet
C=3, h=8, i=9, n=14, a=1 answer May 9 by anonymous

Each word is equal to the sum of the alphabetical number of each letter in that word.
For example FRAUD = 6+18+1+21+4 = 50.
Therefore, CHINA = 3+8+9+14+1 = 35

• Ulhas Shinde answer May 18 by anonymous

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