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15 men take 21 days of 8 hours each for a work. How many days of 6 hours each would 21 women take (3 women= 2 men)?

+1 vote
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If 15 men take 21 days of 8 hours each to do a piece of work. How many days of 6 hours each would 21 women take, if 3 women do as much work as 2 men?

posted Oct 9, 2014 by Vikram Luthra

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2 Answers

+2 votes

15 men take 21 days of 8 hrs. each to do a piece of work.
How many days of 6 hrs. each would it take for 21 women if 3 women do as much work as 2 men?
:
Find the no. of man-hrs to complete the job
15 * 21 * 8 = 2520 man hrs
:
2 man-hrs = 3 women-hrs
therefore
1 women-hr = 2/3 man-hr
:
let d = no. days for these women to do the job
21 * 2/3 * 6d = 2520
84d = 2520
d = 30 days

answer Oct 9, 2014 by Vrije Mani Upadhyay
+1 vote

30 days
im not 100% sure.. but i used de logic
M1*D1*T1=M2*D2*T2
Given M1=15, D1=21, T1=8hrs, M2=14(21 women=14 men),T2=6hrs,
Therefore, D2= M1*D1*T1 / M2*T2=30

answer Dec 17, 2014 by Sunil Di Maria
Fantastic short method.



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