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If 15 men take 21 days of 8 hours each to do a piece of work. How many days of 6 hours each would 21 women take, if 3 women do as much work as 2 men?
15 men take 21 days of 8 hrs. each to do a piece of work.
How many days of 6 hrs. each would it take for 21 women if 3 women do as much work as 2 men?
Find the no. of man-hrs to complete the job
15 * 21 * 8 = 2520 man hrs
2 man-hrs = 3 women-hrs
1 women-hr = 2/3 man-hr
let d = no. days for these women to do the job
21 * 2/3 * 6d = 2520
84d = 2520
d = 30 days
im not 100% sure.. but i used de logic
Given M1=15, D1=21, T1=8hrs, M2=14(21 women=14 men),T2=6hrs,
Therefore, D2= M1*D1*T1 / M2*T2=30
If 6 men and 8 women can do a piece of work in 10 days and 4 men and 7 women can do it in 12 days, how many days will 4 men and 12 women take to do half of work?
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