# How many solutions are there to satisfy the equation: ONE+TWO+FOUR=THREE

+1 vote
105 views

### How many solutions are there to satisfy the equation: ONE+TWO+FOUR=THREE where each letter represents one digit?

posted Feb 18, 2020

637 + 156 + 9684 = 10477

637 + 186 + 9654 = 10477

657 + 136 + 9684 = 10477

657 + 186 + 9634 = 10477

687 + 136 + 9654 = 10477

687 + 156 + 9634 = 10477

The number of solutions are 6 in number.

Too many... TWO must be 3-digit number, THREE must be 5-digit
T=0 for TWO & THREE.
T=0 discounts T as first digit, its ok for others but not for O, T,  F

Similar Puzzles

How many solutions are there to satisfy the equation: ABC+BCD=CBA where each letter represents one digit?

If a, b, and c are distinct numbers, how many solutions are there to the following equation?

Add together three of the following numbers to score 42.

8
10
12
14
20

Each number can be used as many times as you wish.

How many different combinations are there?

+1 vote

Add together three numbers each time to score 45.

Each number can be used as many times as you wish.

How many different combinations are there?

5 10 15 20 25