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How many solutions are there to satisfy the equation: ONE+TWO+FOUR=THREE

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How many solutions are there to satisfy the equation: ONE+TWO+FOUR=THREE where each letter represents one digit?

posted Feb 18 by anonymous

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1 Answer

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637 + 156 + 9684 = 10477

637 + 186 + 9654 = 10477

657 + 136 + 9684 = 10477

657 + 186 + 9634 = 10477

687 + 136 + 9654 = 10477

687 + 156 + 9634 = 10477

The number of solutions are 6 in number.

answer Feb 21 by Tejas Naik
Too many... TWO must be 3-digit number, THREE must be 5-digit
T=0 for TWO & THREE.
T=0 discounts T as first digit, its ok for others but not for O, T,  F



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