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An English club has 17 players on their squad of which 9 are English players and 8 are foreign players. How many different teams can be selected if the playing eleven has to have 5 English players and 6 foreign players?

3528

There are 9! / (5! * (9-5)!) = 126 combinations of English players and 8! / (6! * (8 - 6)!) =28 combinations of foreign players. Number of different teams--> 126*28= 3528

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