Question

Of five consecutive multiples of three, the lowest is multiplied by two and four is added to give a number that is two thirds more than the average of the five numbers.
What is the highest of the consecutive numbers?

Answer 1

12

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5 consecutive multiples of 3 are: 3x-6, 3x-3, 3x, 3x+3, 3x+6
The lowest is multiplied by two and four is added: (3x-6)*2+4=6x-8
A number that is two thirds more than the average of the five numbers: (3x-6+3x-3+3x+3x+3+3x+6)/5*2/3=2x
As 6x-8=2x --> x=2
The highest of the consecutive numbers: 3x+6=12