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There are 31 students in a class, number of girls is one more then number of guys.
We need to form a team of four students.
All four in the team cannot be from same gender and number of girls and guys in the team should not be equal.
How many ways can such a team be made?
Its obvious that number of girls= 16, boys= 15
Number 0, 2 and 4 in the teams excluded. So teams can be formed as 1 or 3 of the same gender:
1 boy + 3 girls -> Combination 1 of 15 x Combination 3 of 16 = 15 x 560 = 8400
3 boys + 1 girl -> Combination 3 of 15 x Combination 1 of 16 = 455 x 16 = 7280
total -> 8400+7280=15680
There are 13 members in a committee having 7 men and 6 women .
In how many ways a team of 4 persons can be selected in such a way that at least 1 man would be there in the team ?
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In a class of 60 students, where the number of girls is twice that of boys, Kamal, a boy ranked seventeenth from the top. If there are 9 girls ahead of Kamal, how many of boys in rank after him?
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