let first no. be x and second no. be (x+1)
Now accrdng to qsn:
So, the first no. is 89.
Second no. =x+1=89+1=90
Therefore the two consecutive no.s whose sum is 179 are 89 and 90.
You have 64 numbers. What is the least number of comparison needed to find the 2nd smallest out of them?
The average of squares of five consecutive even natural numbers is 792.
What is the ratio of smallest number to largest number?