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If 9999 = 4, 8888 = 8, 1816 = 6, 1212 = 0, then 1919 =?

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If 9999 = 4, 8888 = 8, 1816 = 6, 1212 = 0, then 1919 =?
posted Sep 15, 2014 by anonymous

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1 Answer

+1 vote

Ans : 2

Solution 1:

Counter the number of circle in each digit and add them.

9999 = 4 (each 9 has 1 circle)
8888 = 8 (each 8 has 2 circles so 2 x 4 = 8)
1816 = 3 (8 has one circle and 6 has 1 so 2)
1212 = 0 (no circles in 1 & 2)
Hence,
1919 = 2 ( 2 circles of the number 9)

Solution 2:

9999 = 4  ... each 9 is equal to 1 so (1 + 1 + 1 + 1 = 4)
8888 = 8  ... each 8 is equal to 2 so (2 + 2 + 2 + 2 = 8)
1816 = 3  ? (what is the value of 1 and 6)   ------------------------ equation (1)
1212 = 0  ... so the value of 1 and 2 is  0 ( 0 + 0 + 0 + 0 = 0)
put the value of 1 in equation 1
we'll get  6 = 1  i.e ( 0 + 2 + 0 + 6 = 3)

Hence,
1919 = (0 + 1 + 0 + 1 = 2) //by replacing the value of 1 and 9 with 0 and 1.
Ans is 2
answer Sep 16, 2014 by Arshad Khan



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+2 votes

If 9999=4
8888=8
1999=3
2222=0
Then 1616=?

0 votes

If
5 + 4 => 9
3 + 5 => 9
9 + 1 => 9
1 + 6 => 8
4 + 2 => 8
1 + 7 => 7
5 + 6 => 6
3 + 7 => 3
7 + 0 => 0
Then
8 – 1 => ??

+1 vote

If
1 2 3 = 4 5
2 3 3 = 6 4
3 2 1 = 3 9
8 4 0 = 7 2

Then
1 1 1 = ? ?

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