  # If 9999 = 4, 8888 = 8, 1816 = 6, 1212 = 0, then 1919 =?

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If 9999 = 4, 8888 = 8, 1816 = 6, 1212 = 0, then 1919 =? posted Sep 15, 2014

+1 vote

Ans : 2

Solution 1:

Counter the number of circle in each digit and add them.

``````9999 = 4 (each 9 has 1 circle)
8888 = 8 (each 8 has 2 circles so 2 x 4 = 8)
1816 = 3 (8 has one circle and 6 has 1 so 2)
1212 = 0 (no circles in 1 & 2)
Hence,
1919 = 2 ( 2 circles of the number 9)
``````

Solution 2:

``````9999 = 4  ... each 9 is equal to 1 so (1 + 1 + 1 + 1 = 4)
8888 = 8  ... each 8 is equal to 2 so (2 + 2 + 2 + 2 = 8)
1816 = 3  ? (what is the value of 1 and 6)   ------------------------ equation (1)
1212 = 0  ... so the value of 1 and 2 is  0 ( 0 + 0 + 0 + 0 = 0)
put the value of 1 in equation 1
we'll get  6 = 1  i.e ( 0 + 2 + 0 + 6 = 3)

Hence,
1919 = (0 + 1 + 0 + 1 = 2) //by replacing the value of 1 and 9 with 0 and 1.
Ans is 2
`````` answer Sep 16, 2014

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+1 vote

HINT:you don't have to be a mathematical genius to solve just observe.............

If 9999=4
8888=8
1999=3
2222=0
Then 1616=?