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132 sq cm
If sides of the rectange are a and b, then we have:
a+b=25 ---> (1)
a^2+b^2=19^2 ---> (2)
(1)^2-(2)= 2a*b => a*b=(25^2-19^2)/2=132 sq cm.
I have a quadrilateral with perimeter 4 and area 1.
Find the maximum value of the product of its diagonal lengths.
The length of a rectangle exceeds its width by 5m. If the width is increased by 1m and the length is decreased by 2m, the area of the new rectangle is 4 sq.m less than the area of the original rectangle. Find the dimensions of the original rectangle.
If the area of a square and rectangle are equal. The side of square is 12 cm and length of the rectangle is 16 cm, then what would be the perimeter of rectangle?
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