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Find the value of 2x^2 + 4zy + 3z^2. Where x = mean, y= median and z= mode of following number 77 104 91 97 131 48 114 119 91 117 122

58804

77,104,91,97,131,48,114,119,91,117,122 x- Mean = sum/count= 101 y- Median= middle term= 104 z- Mode= number given maximum number of times= 91 (appears 2 times) 2x^2 + 4zy + 3z^2= 2*101^2+4*91*104+3*91*2=58804

Find the value of x^2 + 3xyz + 2y^ + 3z^2 where x = Mean , y = Median and z = Mode of following numbers: 83 87 93 97 110 48 114 119 87 118 122

Find the value of x*y*2*z/5 Where x = mean, y = median and z= mode of following number 57 59 56 81 69 55 64 63 81