   # Find the value of 2x^2 + 4zy + 3z^2. Where x = mean, y= median and z= mode of following number.........

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Find the value of 2x^2 + 4zy + 3z^2.
Where
x = mean, y= median and z= mode of following number
77 104 91 97
131 48 114
119 91 117 122 posted Nov 27, 2018
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## 1 Answer

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58804

77,104,91,97,131,48,114,119,91,117,122
x- Mean = sum/count= 101
y- Median= middle term= 104
z- Mode= number given maximum number of times= 91 (appears 2 times)
2x^2 + 4zy + 3z^2= 2*101^2+4*91*104+3*91*2=58804 answer Nov 27, 2018

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