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If two letters are taken at random from the word CANE, what is the probability that none of the letters would be vowels?

+1 vote
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If two letters are taken at random from the word CANE, what is the probability that none of the letters would be vowels?
posted Jul 31, 2018 by Mridul

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2 Answers

+1 vote

1/6


Number of ways of selecting 2 letters of word CANE- 2*(3+2+1)=12
Number of ways selecting 2 vowels- 2 (CN & NC)
Probability- 2/12=1/6

answer Jul 31, 2018 by Hanifa Mammadov
+1 vote
  • Two letters are taken randomly from out of the word "CANE"=12
  • They are {(CA),(AC),(CN),(NC),(CE),(EC),(AN),(NA),(AE),(EA),(NE),(EN)}
  • None of the letter is a vowel =2
  • They are {(CN),(NC)}
    *So,
    =2/12
    =1/6
  • The answer is 1/6
answer Jul 31, 2018 by Bharathi S
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