# If two letters are taken at random from the word CANE, what is the probability that none of the letters would be vowels?

+1 vote
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If two letters are taken at random from the word CANE, what is the probability that none of the letters would be vowels?
posted Jul 31, 2018
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## 2 Answers

+1 vote

1/6

Number of ways of selecting 2 letters of word CANE- 2*(3+2+1)=12
Number of ways selecting 2 vowels- 2 (CN & NC)
Probability- 2/12=1/6

answer Jul 31, 2018
+1 vote
• Two letters are taken randomly from out of the word "CANE"=12
• They are {(CA),(AC),(CN),(NC),(CE),(EC),(AN),(NA),(AE),(EA),(NE),(EN)}
• None of the letter is a vowel =2
• They are {(CN),(NC)}
*So,
=2/12
=1/6
• The answer is 1/6
answer Jul 31, 2018

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