3 men and 3 women are to sit at a round table. In how many different ways can they sit so that no 2 women sit together?

Question

There are 12 different chocolates placed on a table along a straight line. In how many ways can a person choose 4 of them such that no 2 of the chosen chocolates lie next to each other?

Answer 1

The only seating representation possible = MWMWMW.
Men and women can be arranged in 3! Ways in those positions.
Therefore the total possible arrangements = 3! × 3! = 36.