Primes less than 60 = 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53 & 59. = 17 in number

Primes with at least 1 digit being 3 = 3, 13, 23, 31, 37, 43 & 53 = 7 in number

Therefore the probability = **7/17.**

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A prime number less than 60 is randomly picked, what is probability that one of its digit will be 3?

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