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Sum of first 10^10^100 odd numbers = 10^20^100
10^20^100 = 10^10240000000000^10 ==> a^b^a
Where a = 10 & b = 10240000000000
Therefore a + b = 10240000000010.
1, 2, 3, 4, 5, 6, 7, 8, 9, 10
The above are the first 10 positive integers. The product of the numbers before the number __ is the same as the product of the numbers after that number.
First 17 positive integers (1..17) are rearranged into a sequence such that the sum of any two adjacent terms is a perfect square.
What is the sum of the first and last terms of this sequence?
If a, b and c are integers, is it possible that a+b, b+c and c+a are all odd numbers?
Explain with your working....
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