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The numbers should be 3a:7a
If the numbers are 3a and 7a then 3×7×a=231, a=11.
So the numbers are 33 and 77
And the sum of these numbers = 33 + 77 = 110.
The present ages of A,B and C are in proportions 4:5:6. Eight years ago, the sum of their ages was 66. What is the sum of present age of A and C?
Solve this without paper and pen?
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