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What is the sum of the series - 1 + 5 + 13 + 29 + 61....... upto n terms?

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posted Feb 13 by anonymous

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1 Answer

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Here the nth term can be written as T(n) = a + ((2^(n-1) - 1)d) where a = 1, d = 4, n - the order of the term.
finding a summation of the above term will yield the required answer.
∑ T(n) = a*n + 4*(2^(n) - 1) - 4n { ∑ a = a*n, ∑ 2^(n-1) = [(2^(n) - 1) / (2 - 1)], ∑ 4 = 4*n & d = 4 }
∑ T(n) = n*(a - 4) + 4*(2^(n) - 1)
∑ T(n) = 4*(2^(n) - 1) - 3*n

answer Feb 15 by Tejas Naik
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