Answer: 3+1 = 4. Given eqn.: |x−2|2+|x−2|−2=0|x−2|2+|x−2|−2=0 Let , |x−2|=y|x−2|=y ⇒ y2+y−2=0⇒y2+y−2=0 ⇒y=−2or1⇒y=−2or1 ⇒|x−2|=−2,or1⇒|x−2|=−2,or1 Since the roots are real, |x−2|=1|x−2|=1 ⇒x=1or3⇒x=1or3 sum of the roots=3+1=4
Please share all the roots and share your working also?
Suppose α, β, γ are roots of the equation:
x3 + 3x2 – 24x + 1 = 0
Find the value of ∛α + ∛β + ∛γ